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For each value of y, determine whether it is a solution to =9÷y4.y Is it a solution?Yes No32 28 44 48

Question

For each value of y, determine whether it is a solution to =9÷y4.y

Is it a solution?

  • Yes
  • No

Values of y:

  • 32
  • 28
  • 44
  • 48
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Solution

To determine if each value of y y is a solution to the equation 9÷y4=y 9 \div y^4 = y , we can follow these steps:

1. Break Down the Problem

We need to evaluate the expression 9÷y4 9 \div y^4 and check if it equals y y for each provided value of y y .

2. Relevant Concepts

The equation can be rewritten as: 9y4=y \frac{9}{y^4} = y Multiplying both sides by y4 y^4 gives us: 9=y5 9 = y^5 We can find y y by taking the fifth root of 9: y=91/5 y = 9^{1/5}

3. Analysis and Detail

Now, we will evaluate for each value:

  • For y=32 y = 32 : 325 32^5 Clearly 325 32^5 is much greater than 9, thus y=32 y=32 is not a solution.

  • For y=28 y = 28 : 285 28^5 Similar to 32 32 , 285 28^5 is also significantly greater than 9, hence y=28 y=28 is not a solution.

  • For y=44 y = 44 : 445 44^5 Again, 445 44^5 is also greater than 9, therefore y=44 y=44 is not a solution.

  • For y=48 y = 48 : 485 48^5 Likewise, 485 48^5 is much larger than 9, so y=48 y=48 is not a solution.

4. Verify and Summarize

After evaluating each candidate, none of the provided values 32 32 , 28 28 , 44 44 , or 48 48 satisfy the equation 9=y5 9 = y^5 .

Final Answer

None of the values 32 32 , 28 28 , 44 44 , or 48 48 are solutions. Hence:

  • Is it a solution? No for all values.

This problem has been solved

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