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A gold plated silver jewel of mass 90 g & volume 8.3 cm3. If the mass of silver is 84 g, find the density of gold. Take density of silver 10.5 g/cm3.

Question

A gold plated silver jewel of mass 90 g & volume 8.3 cm³.

If the mass of silver is 84 g, find the density of gold.

Take density of silver 10.5 g/cm³.

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Solution

Sure, here is the step by step solution:

Step 1: Find the volume of silver in the jewel. We know that density = mass/volume. So, rearranging the formula, we get volume = mass/density. Given that the mass of silver is 84 g and the density of silver is 10.5 g/cm3, we can substitute these values into the formula to get the volume of silver. Volume of silver = 84 g / 10.5 g/cm3 = 8 cm3.

Step 2: Find the volume of gold in the jewel. We know that the total volume of the jewel is 8.3 cm3 and the volume of silver is 8 cm3. So, the volume of gold in the jewel is the total volume minus the volume of silver. Volume of gold = 8.3 cm3 - 8 cm3 = 0.3 cm3.

Step 3: Find the mass of gold in the jewel. We know that the total mass of the jewel is 90 g and the mass of silver is 84 g. So, the mass of gold in the jewel is the total mass minus the mass of silver. Mass of gold = 90 g - 84 g = 6 g.

Step 4: Find the density of gold. We know that density = mass/volume. So, substituting the mass and volume of gold into the formula, we get the density of gold. Density of gold = 6 g / 0.3 cm3 = 20 g/cm3.

So, the density of gold in the jewel is 20 g/cm3.

This problem has been solved

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