The weight of Zn(At. wt. = 65.38) displaced by a quantity of electricity which displaces 22400 mL of O2 at STP will be

To solve this problem, we need to use Faraday's laws of electrolysis and the concept of molar volume.

Step 1: Determine the moles of O2 At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L or 22400 mL. Therefore, 22400 mL of O2 is equivalent to 1 mole of O2.

Step 2: Determine the moles of Zn From the balanced chemical equation of the reaction, we know that 1 mole of O2 is equivalent to 2 moles of Zn. Therefore, 1 mole of O2 will displace 2 moles of Zn.

Step 3: Calculate the weight of Zn The atomic weight of Zn is given as 65.38. Therefore, the weight of 2 moles of Zn is 2 * 65.38 = 130.76 g.

So, a quantity of electricity which displaces 22400 mL of O2 at STP will displace 130.76 g of Zn.