# If x + y + z = 1, xy + yz + zx = −1 and xyz = −1 , the value of x3 + y3 + z3 = Select an answerA1B2C4D–1

## Question

## Solution 1

The solution to this problem can be found by using the formula for the sum of cubes, which is a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca).

Given that x + y + z = 1, xy + yz + zx = -1, and xyz = -1, we can substitute these values into the formula.

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