The latent heat of vaporisation of water is 2.26 x 105 J kg-1 22.6 x 105 J kg-1 22.6 x 106 J kg-1 6.22 x 105 J kg-1

To address the query regarding the latent heat of vaporization of water, let's follow these steps:

1. Identify the Question

We need to determine the correct value of the latent heat of vaporization of water from the provided options.

2. Relevant Concepts

The latent heat of vaporization is the amount of heat required to convert unit mass of a substance from liquid to gas at constant temperature and pressure. For water, this value is commonly accepted as approximately $2.26 \times 10^6 \, \text{J/kg}$.

3. Analysis of Options

   • Option A: $2.26 \times 10^5 \, \text{J/kg}$ - This is incorrect as it is an order of magnitude lower than the accepted value.
   • Option B: $22.6 \times 10^5 \, \text{J/kg}$ - This is equivalent to $2.26 \times 10^6 \, \text{J/kg}$, which is the correct value.
   • Option C: $22.6 \times 10^6 \, \text{J/kg}$ - This is incorrect; it is an order of magnitude higher than the accepted value.
   • Option D: $6.22 \times 10^5 \, \text{J/kg}$ - This is also incorrect and significantly lower than the accepted value.

4. Verify and Summarize

Comparing the given options with the known value of latent heat of vaporization for water, we conclude that the correct option is B, which represents $2.26 \times 10^6 \, \text{J/kg}$.

Final Answer

The correct value of the latent heat of vaporization of water is $2.26 \times 10^6 \, \text{J/kg}$, corresponding to option B.