The specific heat of water is given as 1.000 cal/(g·°C). To convert this to SI units (Joules per kilogram per Kelvin, J/kg·K), we need to know the conversion factors:

1 cal = 4.184 J
1 g = 0.001 kg
1 °C = 1 K (since specific heat is independent of the temperature scale)

So, we can convert the given specific heat to SI units as follows:

1.000 cal/(g·°C) = 1.000 cal/(g·°C) * (4.184 J/cal) * (1 kg/0.001 g) * (1 K/1 °C)

= 4184 J/(kg·K)

So, the specific heat of water in SI units is 4184 J/(kg·K).

Question

The specific heat of water is given as 1.000 cal/(g·°C). To convert this to SI units (Joules per kilogram per Kelvin, J/kg·K), we need to know the conversion factors:

1 cal = 4.184 J
1 g = 0.001 kg
1 °C = 1 K (since specific heat is independent of the temperature scale)

So, we can convert the given specific heat to SI units as follows:

1.000 cal/(g·°C) = 1.000 cal/(g·°C) * (4.184 J/cal) * (1 kg/0.001 g) * (1 K/1 °C)

= 4184 J/(kg·K)

So, the specific heat of water in SI units is 4184 J/(kg·K).

Knowee AI · Accepted Answer

The specific heat of water is given as 1.000 cal/(g·°C). To convert this to SI units (Joules per kilogram per Kelvin, J/kg·K), we need to know the conversion factors:

1 cal = 4.184 J
1 g = 0.001 kg
1 °C = 1 K (since specific heat is independent of the temperature scale)

So, we can convert the given specific heat to SI units as follows:

1.000 cal/(g·°C) = 1.000 cal/(g·°C) * (4.184 J/cal) * (1 kg/0.001 g) * (1 K/1 °C)

= 4184 J/(kg·K)

So, the specific heat of water in SI units is 4184 J/(kg·K).

The specific heat of water is 1.000 cal/(g·°C). What is the specific heat of water in SI units?

Question

The specific heat of water is 1.000 cal/(g·°C). What is the specific heat of water in SI units?

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