What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}It doesn’t compileSegmentation Fault980
Question
Solution 1
The code you provided will likely result in a Segmentation Fault. This is because you're trying to assign a value to a pointer that hasn't been initialized and doesn't point to a valid memory location. Here's a step-by-step explanation:
int *ptr;
This line declares a pointer to an integer, but Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}It doesn’t compileSegmentation Fault980
What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}098It doesn’t compileSegmentation Fault
What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}
What is the time complexity of this function / algorithm?void f(int n){ int i; for (i = 0; i < n; i += 98) { printf("[%d]\n", i); }}
What is the output of the following C code?#include <stdio.h>void foo() { printf("Hello, World!\n");}int main() { foo(); return 0;}