What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}

Question

What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}
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Solution 1

The code you've written is in C language and it's trying to assign a value to a pointer without initializing it first. This is undefined behavior in C.

Here's a step by step explanation:

  1. int *ptr; This line declares a pointer to an integer. However, it doesn't initialize the pointer, so it p Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
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