Determine the height of a geosynchronoussatellite above the surface of the earth.Take :G = − −× 11 2 26.67 10 N-m kg= × 6ER 6.37 10 m= × 24EM 5.97 10 kg

To determine the height of a geosynchronous satellite above the surface of the earth, we can use the formula:

h = (G * M * T^2) / (4 * π^2)^(1/3) - R

where:

• G is the gravitational constant (6.67 * 10^-11 N-m^2/kg^2)
• M is the mass of the earth (5.97 * 10^24 kg)
• T is the period of the satellite (24 hours)
• π is the mathematical constant pi (approximately 3.14159)
• R is the radius of the earth (6.37 * 10^6 m)

Plugging in the given values, we have:

h = ((6.67 * 10^-11 N-m^2/kg^2) * (5.97 * 10^24 kg) * (24 hours)^2) / ((4 * (3.14159)^2)^(1/3)) - (6.37 * 10^6 m)

Simplifying the equation, we can calculate the height of the geosynchronous satellite above the surface of the earth.