A pendulum of length 1m and period 2.01s is placed at the top of MountEveresthaving an altitude of 8849m. Calculate the value of ‘g’ at that point.
Question
A pendulum of length 1m and period 2.01s is placed at the top of Mount Everest having an altitude of 8849m. Calculate the value of ‘g’ at that point.
Solution
Sure, let's solve this step by step.
The formula for the period of a pendulum is given by:
T = 2π √(L/g)
where: T = period of the pendulum L = length of the pendulum g = acceleration due to gravity
We can rearrange this formula to solve for g:
g = 4π²L/T²
Substituting the given values:
L = 1m T = 2.01s
g = 4π²(1m)/(2.01s)²
Calculate the above expression to get the value of 'g' at the top of Mount Everest.
Similar Questions
A ball is thrown up at a speed of 4 m/s. Find maximum height reached by the ballis ____ (take 210 /g m s )A) 8 mts B) -8 mts C) 0.80 mts D) -0.8 mts
Calculate the frequency of a simple pendulum, if its length is 50 cm.(Note: The acceleration due to gravity ‘g’ is 9.8 m/s2.
(b) On Mars, where gMars = 3.7 m/s2, the length of a pendulum with a 1.9-s period isLMars = gMarsT24𝜋2 = m/s2 s 2 4𝜋2 = m = cm.
Calculate the velocity of the bob of a simple pendulum at its mean position if it is able to rise a vertical height of 10 cm. (Take g = 10 m/s2)
the period of a simple pendulum is 1s on earth when brought to a planet where g is one-tenth that of the earth its period become
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.