The code you provided has an infinite loop because the decrement of the variable `x` is not inside the while loop. This means that the value of `x` is never updated during the loop, so the condition `math.sqrt(x) 0` is always true. As a result, the program will print "Square root larger than 0" indefinitely.

However, if you intended to decrement `x` within the loop, the corrected code should look like this:

```python
import math
x = 100
while(math.sqrt(x) 0):
print("Square root larger than 0")
x -= 5
```

In this case, the program will print "Square root larger than 0" as long as the square root of `x` is greater than 0. The value of `x` is decremented by 5 in each iteration. When `x` becomes negative, `math.sqrt(x)` will throw a `ValueError` because math.sqrt() does not support negative numbers.

Question

The code you provided has an infinite loop because the decrement of the variable `x` is not inside the while loop. This means that the value of `x` is never updated during the loop, so the condition `math.sqrt(x) > 0` is always true. As a result, the program will print "Square root larger than 0" indefinitely.

However, if you intended to decrement `x` within the loop, the corrected code should look like this:

```python
import math
x = 100
while(math.sqrt(x) > 0): 
    print("Square root larger than 0")
    x -= 5
```

In this case, the program will print "Square root larger than 0" as long as the square root of `x` is greater than 0. The value of `x` is decremented by 5 in each iteration. When `x` becomes negative, `math.sqrt(x)` will throw a `ValueError` because math.sqrt() does not support negative numbers.

Knowee AI · Accepted Answer

The code you provided has an infinite loop because the decrement of the variable `x` is not inside the while loop. This means that the value of `x` is never updated during the loop, so the condition `math.sqrt(x) > 0` is always true. As a result, the program will print "Square root larger than 0" indefinitely.

However, if you intended to decrement `x` within the loop, the corrected code should look like this:

```python
import math
x = 100
while(math.sqrt(x) > 0): 
    print("Square root larger than 0")
    x -= 5
```

In this case, the program will print "Square root larger than 0" as long as the square root of `x` is greater than 0. The value of `x` is decremented by 5 in each iteration. When `x` becomes negative, `math.sqrt(x)` will throw a `ValueError` because math.sqrt() does not support negative numbers.

What does the following code print?import mathx=100while(math.sqrt(x)>0): print("Square root larger than 0")x -= 5

Question

What does the following code print?

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