What does the following code do?x = 5while x > 0: x -= 1 if x == 2: break print(x, end=' ')Answer area4 3 2 1 04 3 24 35 4 3
Question
What does the following code do?
x = 5
while x > 0:
x -= 1
if x == 2:
break
print(x, end=' ')
Answer area
4 3 2 1 0
4 3 2
4 3 5
4 3
Solution
The given code is written in Python. Here's what it does:
- It first sets the variable
x
to 5. - Then it enters a while loop that continues as long as
x
is greater than 0. - Inside the loop, it subtracts 1 from
x
in each iteration. - Then it checks if
x
is equal to 2. Ifx
is 2, it breaks out of the loop. - If
x
is not 2, it prints the current value ofx
, followed by a space. - This process repeats until
x
is no longer greater than 0 or untilx
equals 2.
So, the output of this code will be: 4 3
Similar Questions
What is the output of the following code? for i in range(1, 5):if i == 3: breakprint(i)Answer area1 2 31 21 2 3 41 2 4
What is the output of the following?ct = 2while True: if ct % 0O6 == 0: break print(ct) ct += 1Options2345error.None of these2 3 4 5 6
What is the output of the following few lines of code?1234x=0while(x<2): print(x) x=x+1 1 point010120134
What is the output of the following?ct = 9True = Falsewhile True: print(ct+3) breakOptionsFalse.Error.12True.
What is the output of the following code?a = [1, 2, 3, 4]for x in a: if x == 3: break print(x)121231234Error
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.