Find the solution of the system of equations.8, x, minus, 10, y, equals, 288x−10y=284, x, minus, y, equals, 64x−y=6

The system of equations you provided seems to be a bit mixed up. However, I'll try to interpret it as:

1. 8x - 10y = 288
2. x - y = 6

Here's how you can solve it:

Step 1: Rearrange the second equation to solve for x: x = y + 6

Step 2: Substitute x in the first equation with y + 6: 8(y + 6) - 10y = 288

Step 3: Simplify the equation: 8y + 48 - 10y = 288

Step 4: Combine like terms: -2y + 48 = 288

Step 5: Subtract 48 from both sides: -2y = 240

Step 6: Divide both sides by -2: y = -120

Step 7: Substitute y = -120 into the second equation: x = -120 + 6 = -114

So, the solution to the system of equations is x = -114 and y = -120.