The complex [Cr(ox)2ClBr]3– has two bidentate oxalate ligands, one chloride ligand, and one bromide ligand.

The oxalate ligands are bidentate, meaning they can bind to the chromium atom in two places. This creates a chelate ring, which is rigid and cannot be easily rotated. Therefore, the oxalate ligands do not create any stereoisomers.

The chloride and bromide ligands, however, can create stereoisomers. They can either be trans to each other (opposite sides of the chromium atom) or cis to each other (same side of the chromium atom).

Therefore, there are two possible stereoisomers for this complex: one where the chloride and bromide are trans to each other, and one where they are cis to each other.

So, the total number of stereoisomers for the complex [Cr(ox)2ClBr]3– is 2.

Question

The complex [Cr(ox)2ClBr]3– has two bidentate oxalate ligands, one chloride ligand, and one bromide ligand.

The oxalate ligands are bidentate, meaning they can bind to the chromium atom in two places. This creates a chelate ring, which is rigid and cannot be easily rotated. Therefore, the oxalate ligands do not create any stereoisomers.

The chloride and bromide ligands, however, can create stereoisomers. They can either be trans to each other (opposite sides of the chromium atom) or cis to each other (same side of the chromium atom).

Therefore, there are two possible stereoisomers for this complex: one where the chloride and bromide are trans to each other, and one where they are cis to each other.

So, the total number of stereoisomers for the complex [Cr(ox)2ClBr]3– is 2.

Knowee AI · Accepted Answer

The complex [Cr(ox)2ClBr]3– has two bidentate oxalate ligands, one chloride ligand, and one bromide ligand.

The oxalate ligands are bidentate, meaning they can bind to the chromium atom in two places. This creates a chelate ring, which is rigid and cannot be easily rotated. Therefore, the oxalate ligands do not create any stereoisomers.

The chloride and bromide ligands, however, can create stereoisomers. They can either be trans to each other (opposite sides of the chromium atom) or cis to each other (same side of the chromium atom).

Therefore, there are two possible stereoisomers for this complex: one where the chloride and bromide are trans to each other, and one where they are cis to each other.

So, the total number of stereoisomers for the complex [Cr(ox)2ClBr]3– is 2.

The total number of stereoisomers for the complex [Cr(ox)2ClBr]3–[Cr(ox)2ClBr]3– (where ox = oxalate) isA3

Question

The total number of stereoisomers for the complex `[Cr(ox)2ClBr]^{3-}` (where ox = oxalate) is

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