What are the number of possible isomers of an octahedral complex: [Co(C2O4)2(NH3)2]– (including stereoisomers)?
Question
What are the number of possible isomers of an octahedral complex: [Co(C2O4)2(NH3)2]– (including stereoisomers)?
🧐 Not the exact question you are looking for?Go ask a question
Solution 1
The complex [Co(C2O4)2(NH3)2]– is an octahedral complex with two bidentate oxalate ions (C2O4)2- and two monodentate ammonia ligands (NH3).
- Geometrical Isomers: In octahedral complexes, geometrical isomerism is possible when there are at least two different types of ligands. In this complex, the Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
What are the number of possible isomers of an octahedral complex: [Co(C2O4)2(NH3)2]– (including stereoisomers)?
The total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4]
Find out the number of geometrical isomer(s) possible for the complex [Co(NH3)3(NO2)3].
Total number of possible stereoisomers of the following co-ordinate compound Mabcdef where - a, b, c, d, e and f are mono dentate ligands.
Total number of isomeric compounds (including stereoisomers) formed by monochlorination of 2 -methylbutane is _______.
1/3