Number of ambidentate ligands in a representative metal complex [M(en)(SCN)4] is _________. [en=ethylenediamine]
Question
Number of ambidentate ligands in a representative metal complex
[M(en)(SCN)_4]
where en = ethylenediamine
is ________.
Solution
The metal complex [M(en)(SCN)4] contains two types of ligands: en (ethylenediamine) and SCN (thiocyanate).
Ethylenediamine (en) is a bidentate ligand, meaning it can bind to the metal atom at two points. However, it is not an ambidentate ligand because it does not have two different atoms that can bind to the metal.
On the other hand, thiocyanate (SCN) is an ambidentate ligand because it can bind to the metal atom through either the sulfur atom (S) or the nitrogen atom (N).
Therefore, in the given metal complex [M(en)(SCN)4], there is only one type of ambidentate ligand, which is SCN. So, the number of ambidentate ligands in the complex is 1.
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