Find the remainder when x2 – 6x + 5 is divided by (x + 2).radio_button_unchecked3radio_button_unchecked4radio_button_unchecked21radio_button_unchecked0

To find the remainder when x^2 - 6x + 5 is divided by (x + 2), we can use polynomial division or synthetic division. Here, I'll use synthetic division.

Step 1: Write down the coefficients of the dividend (x^2 - 6x + 5), which are 1, -6, and 5.

Step 2: Write down the zero of the divisor (x + 2), which is -2.

Step 3: Set up the synthetic division table. Write -2 on the left, then write the coefficients (1, -6, 5) to the right.

Step 4: Bring down the first coefficient (1). Multiply -2 by 1, and write the result (-2) under the second coefficient (-6). Add -6 and -2 to get -8.

Step 5: Multiply -2 by -8, and write the result (16) under the third coefficient (5). Add 5 and 16 to get 21.

So, the remainder when x^2 - 6x + 5 is divided by (x + 2) is 21.