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What is the solution to this equation?2(40−5y)=10y+5(1−y)2⁢(40-5⁢𝑦)=10⁢𝑦+5⁢(1-𝑦)

Question

What is the solution to this equation?

2(40−5y)=10y+5(1−y) 2(40 - 5y) = 10y + 5(1 - y)

2(40−5𝑦)=10𝑦+5(1−𝑦) 2(40 - 5𝑦) = 10𝑦 + 5(1 - 𝑦)

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Solution

Sure, let's solve the equation step by step:

The given equation is: 2(40−5y)=10y+5(1−y)

Step 1: Distribute the numbers outside the parentheses on both sides of the equation:

80 - 10y = 10y + 5 - 5y

Step 2: Simplify both sides of the equation:

80 - 10y = 5y + 5

Step 3: Move all the y terms to one side of the equation and the constants to the other side:

10y + 5y = 80 - 5

Step 4: Simplify both sides of the equation:

15y = 75

Step 5: Divide both sides of the equation by 15 to solve for y:

y = 75 / 15

So, the solution to the equation is y = 5.

This problem has been solved

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