Construct the DAG for the following code segment:main( ){inti= 0, n=10; int a(n];while(i<n-1){a[i] =i*i;i=i+1;}Return;}

To construct the Directed Acyclic Graph (DAG) for the given code segment, we need to understand the flow of the code and the dependencies between the operations. Here are the steps:

1. Start with the initializations: int i=0, n=10; int a[n];. These are the initial nodes of the DAG.

2. The next operation is the while loop: while(i<n-1). This is a control flow operation and will be represented as a decision node in the DAG.

3. Inside the loop, we have two operations: a[i] = i*i; and i = i+1;. These operations are dependent on the current value of i and will be represented as nodes in the DAG connected to the i node.

4. The operation a[i] = i*i; is dependent on the current value of i and the result of the operation i*i. This will be represented as a node in the DAG connected to the i node and the node representing the operation i*i.

5. The operation i = i+1; is dependent on the current value of i and will be represented as a node in the DAG connected to the i node.

6. The loop will continue until i<n-1 is false. This will be represented in the DAG as a back edge from the end of the loop to the decision node.

7. Finally, the return; statement is the end of the function and will be represented as the final node in the DAG.

Please note that the actual visual representation of the DAG would depend on the specific tool or method you are using to draw the graph.