main( ){int i, j ;for ( i = 1 ; i <= 2 ; i++ ){for ( j = 1 ; j <= 2 ; j++ ){if ( i == j )continue ;printf ( “n%d %dn”, i, j ) ;}}}1 22 12 11 23 22 3Error

The code you've posted is written in C language. It's a simple program that uses nested for loops and an if condition to print out certain values of i and j. However, there seems to be a syntax error in your printf statement. The correct syntax for printf in C language is to use double quotes (" "), not the stylized quotes (“ ”).

Here's the corrected code:

#include<stdio.h>

main( ){
    int i, j;
    for ( i = 1 ; i <= 2 ; i++ ){
        for ( j = 1 ; j <= 2 ; j++ ){
            if ( i == j )
                continue ;
            printf ( "%d %d\n", i, j ) ;
        }
    }
}

This program will print the values of i and j when they are not equal. The 'continue' statement skips the rest of the current loop iteration and continues with the next iteration. So, when i is equal to j, the printf statement is skipped.

The output of this program will be:

1 2
2 1

This is because when i and j are both 1, the printf statement is skipped due to the 'continue' statement. The same happens when i and j are both 2. The other combinations (i=1, j=2 and i=2, j=1) are printed out.