Here is a table of values for a linear relationship (straight line).𝑥0246𝑦−3159 Use the table to find the equation of the line in the form 𝑦=𝑚𝑥+𝑐.𝑦=

Question

Here is a table of values for a linear relationship (straight line).

$x \quad 0 \quad 2 \quad 4 \quad 6 \quad$
$y \quad -3 \quad 1 \quad 5 \quad 9 \quad$
Use the table to find the equation of the line in the form $y = mx + c$ .
( y = \

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the equation of the line in the form y = mx + c, we first need to find the slope (m) and the y-intercept (c).

Step 1: Find the slope (m) The slope of a line is the change in y divided by the change in x. From the table, we can take two points to calculate this. Let's take the points (0, -3) and (2, 1).

m = (y2 - y1) / (x2 - x1) m = (1 - (-3)) / (2 - 0) m = 4 / 2 m = 2

Step 2: Find the y-intercept (c) The y-intercept is the value of y when x = 0. From the table, we can see that when x = 0, y = -3. So, c = -3.

Therefore, the equation of the line is y = 2x - 3.

This problem has been solved

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.

Here is a table of values for a linear relationship (straight line).𝑥0246𝑦−3159 Use the table to find the equation of the line in the form 𝑦=𝑚𝑥+𝑐.𝑦=

Question