A spring has a spring constant of 120 N/m, and an unstretched length of 0.5m.What force is required to stretch the spring from 0.5m, to 0.6m?

The force required to stretch or compress a spring is given by Hooke's Law, which states that the force (F) is equal to the spring constant (k) times the displacement (x), or F = kx.

In this case, the spring constant (k) is given as 120 N/m. The displacement (x) is the change in length of the spring, which is the final length minus the initial length. Here, the final length is 0.6m and the initial length is 0.5m, so the displacement is 0.6m - 0.5m = 0.1m.

Substituting these values into Hooke's Law gives:

F = kx F = 120 N/m * 0.1m F = 12 N

So, a force of 12 Newtons is required to stretch the spring from 0.5m to 0.6m.