Calculate Oxidation Number of under lined atom in KMnO4Select an answerA– 7B+5C+7D+3

1. Break Down the Problem

To find the oxidation number of manganese (Mn) in potassium permanganate (KMnO₄), we need to consider the oxidation states of the other elements in the compound.

2. Relevant Concepts

• The sum of the oxidation numbers in a neutral compound is equal to zero.
• The oxidation number of potassium (K) is +1.
• The oxidation number of oxygen (O) is typically -2.

3. Analysis and Detail

1. Write the equation based on oxidation states: $\text{Oxidation Number of K} + \text{Oxidation Number of Mn} + 4 \times \text{Oxidation Number of O} = 0$ Substituting the known values: $+1 + \text{Oxidation Number of Mn} + 4 \times (-2) = 0$

2. Calculate: $+1 + \text{Oxidation Number of Mn} - 8 = 0$ $\text{Oxidation Number of Mn} - 7 = 0$ $\text{Oxidation Number of Mn} = +7$

4. Verify and Summarize

The calculated oxidation number for Mn in KMnO₄ is +7.

Final Answer

The oxidation number of Mn in KMnO₄ is +7 (C).