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Show that, when a proton collides with anegative pion ( __ud), the collision productscan be a neutron and an uncharged pion.

Question

Show that, when a proton collides with a negative pion ( π \pi^- ), the collision products can be a neutron and an uncharged pion.

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Solution

Sure, let's go through this step by step:

  1. First, let's identify the particles involved in the collision: a proton and a negative pion. A proton is made up of two up quarks and one down quark (uud), while a negative pion is made up of an up quark and an anti-down quark (u anti-d).

  2. In the collision, one of the up quarks in the proton can interact with the anti-down quark in the negative pion. This interaction can produce a W- boson, which is a force carrier particle involved in the weak nuclear force.

  3. The W- boson can then decay into a down quark and an anti-up quark. The down quark can combine with the remaining up and down quarks in the proton to form a neutron (udd), while the anti-up quark can combine with the up quark in the negative pion to form an uncharged pion (u anti-u).

  4. Therefore, the collision of a proton and a negative pion can indeed produce a neutron and an uncharged pion. This process conserves charge, as the initial and final states both have a total charge of +1. It also conserves baryon number, as the initial and final states both have a total baryon number of +1. Finally, it conserves strangeness, as there are no strange quarks involved in the process.

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