What is the specific heat capacity of a 5.0kg object that needs 67500J to have its temperature raised by 30 ∘ C?
Question
What is the specific heat capacity of a 5.0 kg object that needs 67500 J to have its temperature raised by 30 ∘ C?
Solution
The specific heat capacity (c) of an object can be calculated using the formula:
c = Q / (m * ΔT)
where: Q = heat energy absorbed or released (in joules, J) m = mass of the object (in kilograms, kg) ΔT = change in temperature (in degrees Celsius, °C)
Given: Q = 67500 J m = 5.0 kg ΔT = 30 °C
Substitute the given values into the formula:
c = 67500 J / (5.0 kg * 30 °C) = 450 J/(kg°C)
So, the specific heat capacity of the object is 450 J/(kg°C).
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