What is the specific heat capacity of a 5.0kg object that needs 67500J to have its temperature raised by 30 ∘ C?
Question
Solution 1
The specific heat capacity (c) of an object can be calculated using the formula:
c = Q / (m * ΔT)
where: Q = heat energy absorbed or released (in joules, J) m = mass of the object (in kilograms, kg) ΔT = change in temperature (in degrees Celsius, °C)
Given: Q = 67500 J m = 5.0 kg ΔT = 30 °C
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