The question seems to be a bit jumbled, but I believe you're asking for the difference quotient of the function f(x) = 5x^2 + 6x. The difference quotient is typically represented as [f(x + h) - f(x)] / h. Here's how you can compute it:

1. First, compute f(x + h): Replace every instance of x in the function with (x + h). This gives you f(x + h) = 5(x + h)^2 + 6(x + h).

2. Expand that to get f(x + h) = 5x^2 + 10hx + 5h^2 + 6x + 6h.

3. Now, compute [f(x + h) - f(x)]. This means you subtract the original function f(x) = 5x^2 + 6x from the expanded f(x + h) we just found. This gives you [f(x + h) - f(x)] = 5x^2 + 10hx + 5h^2 + 6x + 6h - (5x^2 + 6x) = 10hx + 5h^2 + 6h.

4. Finally, divide that by h to get the difference quotient: [f(x + h) - f(x)] / h = (10hx + 5h^2 + 6h) / h = 10x + 5h + 6.

So, the difference quotient of the function f(x) = 5x^2 + 6x is 10x + 5h + 6.

Question

The question seems to be a bit jumbled, but I believe you're asking for the difference quotient of the function f(x) = 5x^2 + 6x. The difference quotient is typically represented as [f(x + h) - f(x)] / h. Here's how you can compute it:

1. First, compute f(x + h): Replace every instance of x in the function with (x + h). This gives you f(x + h) = 5(x + h)^2 + 6(x + h).

2. Expand that to get f(x + h) = 5x^2 + 10hx + 5h^2 + 6x + 6h.

3. Now, compute [f(x + h) - f(x)]. This means you subtract the original function f(x) = 5x^2 + 6x from the expanded f(x + h) we just found. This gives you [f(x + h) - f(x)] = 5x^2 + 10hx + 5h^2 + 6x + 6h - (5x^2 + 6x) = 10hx + 5h^2 + 6h.

4. Finally, divide that by h to get the difference quotient: [f(x + h) - f(x)] / h = (10hx + 5h^2 + 6h) / h = 10x + 5h + 6.

So, the difference quotient of the function f(x) = 5x^2 + 6x is 10x + 5h + 6.

Knowee AI · Accepted Answer

The question seems to be a bit jumbled, but I believe you're asking for the difference quotient of the function f(x) = 5x^2 + 6x. The difference quotient is typically represented as [f(x + h) - f(x)] / h. Here's how you can compute it:

1. First, compute f(x + h): Replace every instance of x in the function with (x + h). This gives you f(x + h) = 5(x + h)^2 + 6(x + h).

2. Expand that to get f(x + h) = 5x^2 + 10hx + 5h^2 + 6x + 6h.

3. Now, compute [f(x + h) - f(x)]. This means you subtract the original function f(x) = 5x^2 + 6x from the expanded f(x + h) we just found. This gives you [f(x + h) - f(x)] = 5x^2 + 10hx + 5h^2 + 6x + 6h - (5x^2 + 6x) = 10hx + 5h^2 + 6h.

4. Finally, divide that by h to get the difference quotient: [f(x + h) - f(x)] / h = (10hx + 5h^2 + 6h) / h = 10x + 5h + 6.

So, the difference quotient of the function f(x) = 5x^2 + 6x is 10x + 5h + 6.

Find the difference quotient −f+xhfxh, where ≠h0, for the function below.=fx+5x26x

Question

Find the difference quotient $-f + xhfxh$ , where $h \neq 0$ , for the function below.\n\n= $f(x) + 5x^2 6x$

Solution

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