In the Ru(OH)22+ cation, the Ru atom has an oxidation number of:A.0B.+2C.+4D.+6

Question

In the Ru(OH)22+ cation, the Ru atom has an oxidation number of:A.0B.+2C.+4D.+6
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Solution 1

The oxidation number of a monatomic ion is equal to the charge of the ion. In the Ru(OH)2 2+ cation, the overall charge is +2.

However, we know that the hydroxide ion (OH-) has a charge of -1. Since there are two hydroxide ions, their total charge is -2.

In order for the overall charge of the ca Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

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