In the Ru(OH)22+ cation, the Ru atom has an oxidation number of:A.0B.+2C.+4D.+6
Question
In the Ru(OH)₂²⁺ cation, the Ru atom has an oxidation number of:
A. 0
B. +2
C. +4
D. +6
Solution
The oxidation number of a monatomic ion is equal to the charge of the ion. In the Ru(OH)2 2+ cation, the overall charge is +2.
However, we know that the hydroxide ion (OH-) has a charge of -1. Since there are two hydroxide ions, their total charge is -2.
In order for the overall charge of the cation to be +2, the Ru atom must have an oxidation number of +4 to counteract the -2 charge from the two hydroxide ions.
So, the Ru atom has an oxidation number of +4.
Therefore, the correct answer is C. +4.
Similar Questions
In the Ru(OH)22+ cation, the Ru atom has an oxidation number of:A.0B.+2C.+4D.+6
For an ion, the oxidation number is __.Multiple choice question.one less than the charge on the ionalways negativezerothe same as the charge on the ion
Write the net ionic reaction for the neutralization of Sr(OH)2 and H2SO4.View keyboard shortcutsEditViewInsertFormatToolsTable12ptParagraph
Based on its elemental classification, this atom of Scandium would have an oxidation number of
The Oxygen Family element, Selenium (Se) has a valence number of , and an oxidation number of .
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.