Knowee
Questions
Features
Study Tools

The correct order of bond order among following species isI. NO–3NO3–II.  NO+2NO2+III. He2  IV. O2–2O22–

Question

The correct order of bond order among following species is

  1. NO₃⁻
  2. NO₂⁺
  3. He₂
  4. O₂²⁻
🧐 Not the exact question you are looking for?Go ask a question

Solution

1. Break Down the Problem

To determine the correct order of bond order among the given species (NO₃⁻, NO₂⁺, He₂, O₂²⁻, and O₂), we first need to calculate the bond order for each species individually.

2. Relevant Concepts

The bond order can be calculated using the formula:

Bond Order=(Number of bonding electronsNumber of antibonding electrons)2 \text{Bond Order} = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2}

3. Analysis and Detail

  1. For NO₃⁻:

    • Nitrogen has five valence electrons, and each oxygen has six.
    • The total number of valence electrons = 5+3×6+1=245 + 3 \times 6 + 1 = 24 (adding one for the negative charge).
    • This results in resonance structures that primarily contribute to a bond order of 1.

    Bond Order (NO₃⁻)=1 \text{Bond Order (NO₃⁻)} = 1

  2. For NO₂⁺:

    • Nitrogen has five valence electrons and each oxygen has six.
    • The total number of valence electrons = 5+2×61=165 + 2 \times 6 - 1 = 16 (subtracting one for the positive charge).
    • The bond order for NO₂⁺ is calculated as follows:

    Bond Order (NO₂⁺)=2 \text{Bond Order (NO₂⁺)} = 2

  3. For He₂:

    • Helium has two electrons.
    • Total electrons = 2 (bonding) in the σ(1s) orbital.
    • There are no antibonding electrons in He₂.

    Bond Order (He₂)=(20)2=1 \text{Bond Order (He₂)} = \frac{(2 - 0)}{2} = 1

  4. For O₂²⁻:

    • Oxygen has six electrons; thus the total for O₂ is 12. For the O₂²⁻, we add two more due to the charges.
    • Total = 12+2=1412 + 2 = 14 electrons.
    • The bond order is calculated:

    Bond Order (O₂²⁻)=(104)2=3 \text{Bond Order (O₂²⁻)} = \frac{(10 - 4)}{2} = 3

  5. For O₂:

    • O₂ has a total of 12 electrons.
    • The bond order is:

    Bond Order (O₂)=(102)2=4 \text{Bond Order (O₂)} = \frac{(10 - 2)}{2} = 4

4. Verify and Summarize

After calculating, we have:

  • NO₃⁻: Bond Order = 1
  • NO₂⁺: Bond Order = 2
  • He₂: Bond Order = 1
  • O₂²⁻: Bond Order = 3
  • O₂: Bond Order = 4

Final Answer

The correct order of bond order among the species is: NO₃⁻ < He₂ = NO₂⁺ < O₂²⁻ < O₂.

This problem has been solved

Similar Questions

The correct order of bond order among following species isI. NO–3NO3–II.  NO+2NO2+III. He2  IV. O2–2O22–

According to MO theory the bond orders for O22−, CO and NO+ respectively, are1,3 and 31,3 and 21,2 and 32,3 and 3

Identify the correct order of increasing number of π−π- bonds in structures of the following molecules.I. H2S2O6II. H2SO3III. H2S2O5

Based on MO theory, which of the following molecules and ions have the largest bondorder?A. H2 B. H2+C. He2 D. He2+

Which of the following chemical species possess a coordinate bond?H2ONH3H3O+OH–

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.