According to Molecular Orbital (MO) theory, the bond orders for O22−, CO and NO+ are 1, 3 and 2 respectively.

Here's how you calculate it:

1. O22−: Oxygen has 6 valence electrons, so O2 has 12. The extra 2 electrons from the 2- charge gives us 14 electrons. Filling up the MO diagram from lowest energy to highest, we get 10 electrons in bonding orbitals and 4 in antibonding orbitals. The bond order is (10-4)/2 = 1.

2. CO: Carbon has 4 valence electrons and Oxygen has 6, giving us 10 electrons. Filling up the MO diagram, we get 8 electrons in bonding orbitals and 2 in antibonding orbitals. The bond order is (8-2)/2 = 3.

3. NO+: Nitrogen has 5 valence electrons and Oxygen has 6, giving us 11 electrons. The positive charge means we remove one electron, leaving us with 10. Filling up the MO diagram, we get 8 electrons in bonding orbitals and 2 in antibonding orbitals. The bond order is (8-2)/2 = 3.

Question

According to Molecular Orbital (MO) theory, the bond orders for O22−, CO and NO+ are 1, 3 and 2 respectively.

Here's how you calculate it:

1. O22−: Oxygen has 6 valence electrons, so O2 has 12. The extra 2 electrons from the 2- charge gives us 14 electrons. Filling up the MO diagram from lowest energy to highest, we get 10 electrons in bonding orbitals and 4 in antibonding orbitals. The bond order is (10-4)/2 = 1.

2. CO: Carbon has 4 valence electrons and Oxygen has 6, giving us 10 electrons. Filling up the MO diagram, we get 8 electrons in bonding orbitals and 2 in antibonding orbitals. The bond order is (8-2)/2 = 3.

3. NO+: Nitrogen has 5 valence electrons and Oxygen has 6, giving us 11 electrons. The positive charge means we remove one electron, leaving us with 10. Filling up the MO diagram, we get 8 electrons in bonding orbitals and 2 in antibonding orbitals. The bond order is (8-2)/2 = 3.

Knowee AI · Accepted Answer

According to Molecular Orbital (MO) theory, the bond orders for O22−, CO and NO+ are 1, 3 and 2 respectively.

Here's how you calculate it:

1. O22−: Oxygen has 6 valence electrons, so O2 has 12. The extra 2 electrons from the 2- charge gives us 14 electrons. Filling up the MO diagram from lowest energy to highest, we get 10 electrons in bonding orbitals and 4 in antibonding orbitals. The bond order is (10-4)/2 = 1.

2. CO: Carbon has 4 valence electrons and Oxygen has 6, giving us 10 electrons. Filling up the MO diagram, we get 8 electrons in bonding orbitals and 2 in antibonding orbitals. The bond order is (8-2)/2 = 3.

3. NO+: Nitrogen has 5 valence electrons and Oxygen has 6, giving us 11 electrons. The positive charge means we remove one electron, leaving us with 10. Filling up the MO diagram, we get 8 electrons in bonding orbitals and 2 in antibonding orbitals. The bond order is (8-2)/2 = 3.

According to MO theory the bond orders for O22−, CO and NO+ respectively, are1,3 and 31,3 and 21,2 and 32,3 and 3

Question

According to MO theory the bond orders for O₂²⁻, CO and NO⁺ respectively, are 1, 3 and 3 1, 3 and 2 1, 2 and 3 2, 3 and 3

Solution

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