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The value of deltaH-deltaU for the following reaction at 27^°c will be N2+3H2 gives 2NH3

Question

The value of ΔHΔU \Delta H - \Delta U for the following reaction at 27°c will be

N2+3H22NH3 \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3

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Solution

To calculate the value of deltaH-deltaU for the given reaction at 27°C, we need to follow these steps:

Step 1: Determine the enthalpy change (deltaH) of the reaction.

  • Look up the standard enthalpy of formation (deltaHf) values for each compound involved in the reaction.
  • The deltaHf values represent the enthalpy change when one mole of a compound is formed from its elements in their standard states.
  • The deltaHf values for N2, H2, and NH3 are typically provided in reference tables.
  • The deltaH of the reaction can be calculated by subtracting the sum of the deltaHf values of the reactants from the sum of the deltaHf values of the products.
  • In this case, the deltaH of the reaction can be calculated as follows: deltaH = (2 * deltaHf(NH3)) - (deltaHf(N2) + 3 * deltaHf(H2))

Step 2: Determine the internal energy change (deltaU) of the reaction.

  • The internal energy change (deltaU) is related to the enthalpy change (deltaH) by the equation: deltaH = deltaU + P * deltaV, where P is the pressure and deltaV is the change in volume.
  • At constant pressure, the change in volume is typically negligible, so we can assume deltaV is approximately zero.
  • Therefore, deltaH is approximately equal to deltaU.
  • In this case, the value of deltaH-deltaU will be close to zero.

Step 3: Calculate the value of deltaH-deltaU.

  • Since deltaH is approximately equal to deltaU, the value of deltaH-deltaU will be close to zero.
  • Therefore, the value of deltaH-deltaU for the given reaction at 27°C will be close to zero.

Please note that the actual values of deltaH and deltaU for the reaction should be obtained from reliable sources or experimental data to obtain more accurate results.

This problem has been solved

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