What will be the output of the following C code? #include void main() { m(); } void m() { printf("hi"); m(); }a.Compile time errorb.hic.Infinite hid.Nothing
Question
What will be the output of the following C code?
#include <stdio.h>
void main() {
m();
}
void m() {
printf("hi");
m();
}
a. Compile time error
b. hi
c. Infinite hi
d. Nothing
Solution
1. Break Down the Problem
To determine the output of the provided C code, we need to analyze the code structure and flow. The program consists of:
- A
main
function that callsm()
. - A function
m()
that prints "hi" followed by a recursive call tom()
.
2. Relevant Concepts
- The code includes a function with recursive calls.
- As this is a recursive function without a base case, it will continue to call itself indefinitely.
3. Analysis and Detail
- When the code runs, it starts executing from the
main
function. - The function
m()
is called, which executesprintf("hi");
, printing "hi" to the console. - Following that,
m()
calls itself again, creating a new instance of the function. - This process repeats indefinitely because no condition stops the recursion, leading to an infinite loop.
- Given that there is no limit or exit condition, the program will keep running until it exhausts system resources, likely causing a stack overflow.
4. Verify and Summarize
- The program does not return a value; it will continuously print "hi" until it crashes.
- However, no compile-time errors will occur as the code is syntactically correct aside from standard library inclusion.
Final Answer
The output will be c. Infinite hi as "hi" will be printed infinitely until a stack overflow occurs.
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