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What is the output of the following C code?char *ptr;char mystring[] = "abcdefg";ptr = myString;ptr += 5;

Question

What is the output of the following C code?

char *ptr;
char mystring[] = "abcdefg";
ptr = mystring;
ptr += 5;
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Solution

The output of the given code is not specified as it does not contain any code to print or display the value of the variable ptr. However, I can explain what the code does step by step:

  1. Declare a character pointer variable ptr.
  2. Declare a character array mystring and initialize it with the string "abcdefg".
  3. Assign the starting address of mystring to the pointer variable ptr.
  4. Increment the pointer ptr by 5 positions.
    • After this step, ptr will point to the 6th character in the mystring array, which is the character 'g'.

To see the output, you would need to add code to print or display the value of ptr, such as printf("%c", *ptr);.

This problem has been solved

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