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The expression |y(x, t)|2 stands for(a) normalisation (b) position(c) time probability density (d) position probability density

Question

The expression |y(x, t)|^2 stands for

(a) normalisation
(b) position
(c) time probability density
(d) position probability density

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Solution

The expression y(x,t)2|y(x, t)|^2 is commonly encountered in quantum mechanics, particularly in the context of wave functions. Let's analyze the provided options to determine the correct answer:

  1. Understanding the Expression: The term y(x,t)2|y(x, t)|^2 denotes the square of the modulus of a wave function yy that depends on position xx and time tt. In quantum mechanics, this represents a probability density.

  2. Evaluating the Options:

    • (a) Normalization: While y(x,t)2|y(x, t)|^2 is related to normalization of the wave function, it is not the definition itself.
    • (b) Position: This option is not accurate; y(x,t)2|y(x, t)|^2 is not a direct representation of position.
    • (c) Time Probability Density: This is misleading; y(x,t)2|y(x, t)|^2 can vary with time, but it primarily represents the probability density at a given position and time.
    • (d) Position Probability Density: This accurately describes y(x,t)2|y(x, t)|^2. It gives the probability density of finding a particle at position xx at time tt.

Final Answer

The correct answer is (d) position probability density.

This problem has been solved

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