The reaction of carbonic acid (H2CO3) with water is a dissociation reaction, where carbonic acid breaks down into its ions. The reaction can be written as follows:

H2CO3(aq) ⇌ H+(aq) + HCO3-(aq)

The equilibrium constant expression for this reaction is:

K = [H+][HCO3-] / [H2CO3]

In this expression, [H2CO3] is the concentration of carbonic acid, [H+] is the concentration of hydrogen ions, and [HCO3-] is the concentration of bicarbonate ions. The equilibrium constant K describes the ratio of the concentrations of the products to the reactants at equilibrium.

Question

The reaction of carbonic acid (H2CO3) with water is a dissociation reaction, where carbonic acid breaks down into its ions. The reaction can be written as follows:

H2CO3(aq) ⇌ H+(aq) + HCO3-(aq)

The equilibrium constant expression for this reaction is:

K = [H+][HCO3-] / [H2CO3]

In this expression, [H2CO3] is the concentration of carbonic acid, [H+] is the concentration of hydrogen ions, and [HCO3-] is the concentration of bicarbonate ions. The equilibrium constant K describes the ratio of the concentrations of the products to the reactants at equilibrium.

Knowee AI · Accepted Answer

The reaction of carbonic acid (H2CO3) with water is a dissociation reaction, where carbonic acid breaks down into its ions. The reaction can be written as follows:

H2CO3(aq) ⇌ H+(aq) + HCO3-(aq)

The equilibrium constant expression for this reaction is:

K = [H+][HCO3-] / [H2CO3]

In this expression, [H2CO3] is the concentration of carbonic acid, [H+] is the concentration of hydrogen ions, and [HCO3-] is the concentration of bicarbonate ions. The equilibrium constant K describes the ratio of the concentrations of the products to the reactants at equilibrium.

Fill in the left side of this equilibrium constant equation for the reaction of carbonic acid H2CO3 with water.

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