Fill in the left side of this equilibrium constant equation for the reaction of carbonic acid H2CO3 with water.
Question
Solution 1
The reaction of carbonic acid (H2CO3) with water is a dissociation reaction, where carbonic acid breaks down into its ions. The reaction can be written as follows:
H2CO3(aq) ⇌ H+(aq) + HCO3-(aq)
The equilibrium constant expression for this reaction is:
K = [H+][HCO3-] / [H2CO3]
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