Fill in the left side of this equilibrium constant equation for the reaction of phosphoric acid H3PO4 with water.
Question
Fill in the left side of this equilibrium constant equation for the reaction of phosphoric acid H<sub>3</sub>PO<sub>4</sub> with water.
Solution
The reaction of phosphoric acid (H3PO4) with water can be represented as follows:
H3PO4 + H2O ⇌ H2PO4- + H3O+
The equilibrium constant equation for this reaction is:
Ka = [H2PO4-][H3O+] / [H3PO4]
Where:
- [H2PO4-] is the concentration of the dihydrogen phosphate ion at equilibrium.
- [H3O+] is the concentration of the hydronium ion at equilibrium.
- [H3PO4] is the concentration of the phosphoric acid at equilibrium.
The "Ka" is the acid dissociation constant. It is a measure of the strength of the acid. The larger the Ka, the stronger the acid.
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