Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid HC6H5CO2 with water.
Question
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid HC6H5CO2 with water.
Solution
The reaction of benzoic acid (HC6H5CO2) with water can be represented as follows:
HC6H5CO2 (aq) + H2O (l) ⇌ C6H5CO2^- (aq) + H3O^+ (aq)
The equilibrium constant expression for this reaction is:
Ka = [C6H5CO2^-][H3O^+] / [HC6H5CO2]
In this equation, [C6H5CO2^-] is the concentration of the benzoate ion, [H3O^+] is the concentration of the hydronium ion, and [HC6H5CO2] is the concentration of benzoic acid. The equilibrium constant Ka is a measure of the degree of ionization of the benzoic acid.
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