A ball is thrown upward with a velocity of 100 m/s. Find the time taken to reach the ground.
Question
A ball is thrown upward with a velocity of 100 m/s. Find the time taken to reach the ground.
Solution
Sure, let's solve this step by step.
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First, we need to understand the motion of the ball. When a ball is thrown upwards, it will rise until its velocity becomes zero (this is the peak point), then it will start to fall down due to gravity. The total time taken to reach the ground is twice the time taken to reach the peak point.
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The time taken to reach the peak can be calculated using the formula: t = v/g, where v is the initial velocity and g is the acceleration due to gravity.
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Substituting the given values, we get: t = 100/9.8 = 10.2 seconds (approximately). This is the time taken to reach the peak.
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As mentioned earlier, the total time taken to reach the ground is twice the time taken to reach the peak. So, the total time = 2 * 10.2 = 20.4 seconds.
So, the ball will take approximately 20.4 seconds to reach the ground.
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