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Find the numerical value of m if the expression x3 + mx2 + 7x − 6 has a remainder of −4 whendivided by x + 2.

Question

Find the numerical value of m if the expression x3+mx2+7x6 x^3 + mx^2 + 7x - 6 has a remainder of 4-4 when divided by x+2 x + 2 .

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Solution

To find the value of m, we can use the Remainder Theorem which states that the remainder of a polynomial f(x) divided by (x-a) is equal to f(a).

In this case, our polynomial is f(x) = x^3 + mx^2 + 7x - 6 and we are dividing by x + 2, so a = -2.

Substituting a = -2 into the polynomial gives us the remainder, which is -4.

So, we have:

(-2)^3 + m(-2)^2 + 7(-2) - 6 = -4 -8 + 4m - 14 - 6 = -4 4m - 28 = -4 4m = 24 m = 24 / 4 m = 6

So, the numerical value of m is 6.

This problem has been solved

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