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Calculate the average velocity at a particular time interval of a person if he moves from 10 m at 6 s to 24 m at 8 s along the x-axis?6 m/s9 m/s7 m/s50 m/s

Question

Calculate the average velocity at a particular time interval of a person if he moves from 10 m at 6 s to 24 m at 8 s along the x-axis?

Options:

  • 6 m/s
  • 9 m/s
  • 7 m/s
  • 50 m/s
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Solution

1. ### Break Down the Problem

We need to calculate the average velocity of a person moving along the x-axis over a specific time interval. The data given includes:

  • Initial position xi=10mx_i = 10 \, \text{m} at ti=6st_i = 6 \, \text{s}
  • Final position xf=24mx_f = 24 \, \text{m} at tf=8st_f = 8 \, \text{s}

2. ### Relevant Concepts

The formula for average velocity vavgv_{avg} is given by: vavg=xfxitfti v_{avg} = \frac{x_f - x_i}{t_f - t_i}

3. ### Analysis and Detail

Now, substituting the given values into the average velocity formula: vavg=24m10m8s6s v_{avg} = \frac{24 \, \text{m} - 10 \, \text{m}}{8 \, \text{s} - 6 \, \text{s}} vavg=14m2s v_{avg} = \frac{14 \, \text{m}}{2 \, \text{s}} vavg=7m/s v_{avg} = 7 \, \text{m/s}

4. ### Verify and Summarize

Let’s verify the calculation:

  • Displacement is 24m10m=14m24 \, \text{m} - 10 \, \text{m} = 14 \, \text{m}.
  • Time interval is 8s6s=2s8 \, \text{s} - 6 \, \text{s} = 2 \, \text{s}.
  • Using these values confirms vavg=7m/sv_{avg} = 7 \, \text{m/s}.

Final Answer

The average velocity is 7m/s \mathbf{7 \, \text{m/s}} .

This problem has been solved

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