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t takes 10 s for an object to accelerate from 10 m/s to 25 m/s.What is the object's average acceleration?

Question

It takes 10 s for an object to accelerate from 10 m/s to 25 m/s. What is the object's average acceleration?

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Solution

1. Break Down the Problem

To find the average acceleration, we need to:

  1. Identify the initial velocity (viv_i).
  2. Identify the final velocity (vfv_f).
  3. Identify the time period (tt) over which the acceleration occurs.
  4. Apply the formula for average acceleration.

2. Relevant Concepts

The formula for average acceleration (aa) is given by: a=vfvit a = \frac{v_f - v_i}{t} Where:

  • vfv_f is the final velocity.
  • viv_i is the initial velocity.
  • tt is the time taken for the change in velocity.

3. Analysis and Detail

  1. Identify the Values:

    • Initial velocity, vi=10m/sv_i = 10 \, \text{m/s}
    • Final velocity, vf=25m/sv_f = 25 \, \text{m/s}
    • Time, t=10st = 10 \, \text{s}
  2. Substituting the Values into the Formula: a=25m/s10m/s10s a = \frac{25 \, \text{m/s} - 10 \, \text{m/s}}{10 \, \text{s}} a=15m/s10s=1.5m/s2 a = \frac{15 \, \text{m/s}}{10 \, \text{s}} = 1.5 \, \text{m/s}^2

4. Verify and Summarize

The calculations show that the change in velocity is 15m/s15 \, \text{m/s} occurring over 10s10 \, \text{s}, leading to an average acceleration of 1.5m/s21.5 \, \text{m/s}^2.

Final Answer

The object's average acceleration is 1.5m/s21.5 \, \text{m/s}^2.

This problem has been solved

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