What is the Q-point for a biased transistor as in Figure 5–2 with IB = 150 mA, bDC = 75,VCC = 18 V, and RC = 1.0 kV?

The Q-point of a transistor, also known as the quiescent point, is the DC operating point, around which the signal variations occur. It is determined by the DC biasing voltages or currents.

Given the following parameters:

Base current, IB = 150 mA = 150 x 10^-3 A DC current gain, bDC = 75 Collector supply voltage, VCC = 18 V Collector resistor, RC = 1.0 kΩ = 1000 Ω

We can calculate the Q-point using the following steps:

1. Calculate the collector current, IC. This is given by the product of the base current and the DC current gain (IC = IB * bDC). Substituting the given values:

   IC = (150 x 10^-3) * 75 = 11.25 A

2. Calculate the collector-emitter voltage, VCE. This is given by the difference between the collector supply voltage and the product of the collector current and the collector resistor (VCE = VCC - IC * RC). Substituting the given values:

   VCE = 18 - (11.25 * 1000) = -11232 V

Please note that the collector current and collector-emitter voltage values are unrealistic for a typical transistor operation. There might be a mistake in the given parameters, especially the base current seems to be too high for a typical transistor. Please check the values again.