What is the Q-point for a fixed-bias transistor with IB = 75 uA, β = 100, Vcc = 20 V, and Rc = 1.5 k?
Question
What is the Q-point for a fixed-bias transistor with
- IB = 75 µA
- β = 100
- Vcc = 20 V
- Rc = 1.5 kΩ?
Solution
The Q-point of a transistor can be determined by finding the values of the collector current (Ic) and the collector-emitter voltage (Vce).
Step 1: Calculate Ic The collector current (Ic) can be calculated using the formula Ic = β * IB.
Given that β = 100 and IB = 75 uA, we can substitute these values into the formula:
Ic = 100 * 75 uA = 7500 uA = 7.5 mA
Step 2: Calculate Vce The collector-emitter voltage (Vce) can be calculated using the formula Vce = Vcc - Ic * Rc.
Given that Vcc = 20 V, Ic = 7.5 mA, and Rc = 1.5 kΩ, we can substitute these values into the formula:
Vce = 20 V - 7.5 mA * 1.5 kΩ = 20 V - 11.25 V = 8.75 V
Therefore, the Q-point for the given fixed-bias transistor is (Ic, Vce) = (7.5 mA, 8.75 V).
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