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What is the Q-point for a fixed-bias transistor with IB = 75 uA, β = 100, Vcc = 20 V, and Rc = 1.5 k?

Question

What is the Q-point for a fixed-bias transistor with

  • IB = 75 µA
  • β = 100
  • Vcc = 20 V
  • Rc = 1.5 kΩ?
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Solution

The Q-point of a transistor can be determined by finding the values of the collector current (Ic) and the collector-emitter voltage (Vce).

Step 1: Calculate Ic The collector current (Ic) can be calculated using the formula Ic = β * IB.

Given that β = 100 and IB = 75 uA, we can substitute these values into the formula:

Ic = 100 * 75 uA = 7500 uA = 7.5 mA

Step 2: Calculate Vce The collector-emitter voltage (Vce) can be calculated using the formula Vce = Vcc - Ic * Rc.

Given that Vcc = 20 V, Ic = 7.5 mA, and Rc = 1.5 kΩ, we can substitute these values into the formula:

Vce = 20 V - 7.5 mA * 1.5 kΩ = 20 V - 11.25 V = 8.75 V

Therefore, the Q-point for the given fixed-bias transistor is (Ic, Vce) = (7.5 mA, 8.75 V).

This problem has been solved

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