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Solve the below difference equation with Z transform:๐‘ฆ๐‘›+2 + 6๐‘ฆ๐‘›+1 + 9๐‘ฆ๐‘› = 5๐‘›, where ๐‘ฆ0 = ๐‘ฆ1 = 0

Question

Solve the below difference equation with Z transform:

yn+2+6yn+1+9yn=5n,ย whereย y0=y1=0 y_{n+2} + 6y_{n+1} + 9y_{n} = 5^{n}, \text{ where } y_{0} = y_{1} = 0

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Solution

To solve the given difference equation using the Z-transform, we will follow these steps:

Step 1: Take the Z-transform of both sides of the equation.

Applying the Z-transform to the left side of the equation, we get:

Z{๐‘ฆ๐‘›+2} + 6Z{๐‘ฆ๐‘›+1} + 9Z{๐‘ฆ๐‘›} = Z{5๐‘›}

Step 2: Use the Z-transform properties and formulas to simplify the equation.

Using the time-shifting property of the Z-transform, we can rewrite the equation as:

Z{๐‘ฆ๐‘›}Zยฒ + 6Z{๐‘ฆ๐‘›}Z + 9Z{๐‘ฆ๐‘›} = Z{5๐‘›}

Step 3: Substitute the initial conditions ๐‘ฆ0 = ๐‘ฆ1 = 0 into the equation.

Since ๐‘ฆ0 = ๐‘ฆ1 = 0, we can substitute Z{๐‘ฆ0} = Z{๐‘ฆ1} = 0 into the equation:

Zยฒ + 6Z + 9Z{๐‘ฆ๐‘›} = Z{5๐‘›}

Step 4: Solve for Z{๐‘ฆ๐‘›}.

Rearranging the equation, we have:

Z{๐‘ฆ๐‘›} = (Z{5๐‘›} - Zยฒ - 6Z) / 9

Step 5: Inverse Z-transform to find ๐‘ฆ๐‘›.

Using the inverse Z-transform, we can find ๐‘ฆ๐‘› by taking the inverse Z-transform of Z{๐‘ฆ๐‘›}:

๐‘ฆ๐‘› = Inverse Z-transform{(Z{5๐‘›} - Zยฒ - 6Z) / 9}

Step 6: Simplify the expression and find the final solution for ๐‘ฆ๐‘›.

By applying the inverse Z-transform, we can simplify the expression and find the final solution for ๐‘ฆ๐‘›. However, the specific method for finding the inverse Z-transform depends on the given Z-transform table or the Z-transform properties and formulas available to you.

Please note that without the specific Z-transform table or properties, I cannot provide the exact solution for ๐‘ฆ๐‘›.

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