To find the area of the region above the x-axis, included between the parabola 𝑦²=𝑎𝑥 and the circle 𝑥²+𝑦²=2𝑎𝑥, we need to follow these steps:

1. First, we need to find the points of intersection of the parabola and the circle. To do this, we substitute 𝑦²=𝑎𝑥 into the equation of the circle to get 𝑥²+𝑎𝑥=2𝑎𝑥. Simplifying this gives 𝑥²=𝑎𝑥, so 𝑥=𝑎 or 𝑥=0.

2. Now we need to find the y-coordinates of these points of intersection. Substituting 𝑥=𝑎 into 𝑦²=𝑎𝑥 gives 𝑦²=𝑎², so 𝑦=±√𝑎²=±𝑎. Since we are only interested in the region above the x-axis, we take 𝑦=𝑎. Similarly, substituting 𝑥=0 into 𝑦²=𝑎𝑥 gives 𝑦=0.

3. So the points of intersection are (0,0) and (𝑎,𝑎).

4. Now we need to find the area of the region. To do this, we integrate the difference of the functions from 0 to 𝑎. The function for the parabola is √(𝑎𝑥) and the function for the circle is √(2𝑎𝑥-𝑥²).

5. So the area A is given by the integral from 0 to 𝑎 of [√(2𝑎𝑥-𝑥²) - √(𝑎𝑥)] dx.

6. Evaluating this integral will give the area of the region.

Question

To find the area of the region above the x-axis, included between the parabola 𝑦²=𝑎𝑥 and the circle 𝑥²+𝑦²=2𝑎𝑥, we need to follow these steps:

1. First, we need to find the points of intersection of the parabola and the circle. To do this, we substitute 𝑦²=𝑎𝑥 into the equation of the circle to get 𝑥²+𝑎𝑥=2𝑎𝑥. Simplifying this gives 𝑥²=𝑎𝑥, so 𝑥=𝑎 or 𝑥=0.

2. Now we need to find the y-coordinates of these points of intersection. Substituting 𝑥=𝑎 into 𝑦²=𝑎𝑥 gives 𝑦²=𝑎², so 𝑦=±√𝑎²=±𝑎. Since we are only interested in the region above the x-axis, we take 𝑦=𝑎. Similarly, substituting 𝑥=0 into 𝑦²=𝑎𝑥 gives 𝑦=0.

3. So the points of intersection are (0,0) and (𝑎,𝑎).

4. Now we need to find the area of the region. To do this, we integrate the difference of the functions from 0 to 𝑎. The function for the parabola is √(𝑎𝑥) and the function for the circle is √(2𝑎𝑥-𝑥²).

5. So the area A is given by the integral from 0 to 𝑎 of [√(2𝑎𝑥-𝑥²) - √(𝑎𝑥)] dx.

6. Evaluating this integral will give the area of the region.

Knowee AI · Accepted Answer

To find the area of the region above the x-axis, included between the parabola 𝑦²=𝑎𝑥 and the circle 𝑥²+𝑦²=2𝑎𝑥, we need to follow these steps:

1. First, we need to find the points of intersection of the parabola and the circle. To do this, we substitute 𝑦²=𝑎𝑥 into the equation of the circle to get 𝑥²+𝑎𝑥=2𝑎𝑥. Simplifying this gives 𝑥²=𝑎𝑥, so 𝑥=𝑎 or 𝑥=0.

2. Now we need to find the y-coordinates of these points of intersection. Substituting 𝑥=𝑎 into 𝑦²=𝑎𝑥 gives 𝑦²=𝑎², so 𝑦=±√𝑎²=±𝑎. Since we are only interested in the region above the x-axis, we take 𝑦=𝑎. Similarly, substituting 𝑥=0 into 𝑦²=𝑎𝑥 gives 𝑦=0.

3. So the points of intersection are (0,0) and (𝑎,𝑎).

4. Now we need to find the area of the region. To do this, we integrate the difference of the functions from 0 to 𝑎. The function for the parabola is √(𝑎𝑥) and the function for the circle is √(2𝑎𝑥-𝑥²).

5. So the area A is given by the integral from 0 to 𝑎 of [√(2𝑎𝑥-𝑥²) - √(𝑎𝑥)] dx.

6. Evaluating this integral will give the area of the region.

Find the area of the region above the x-axis, included between the parabola 𝑦2=𝑎𝑥 and the circle 𝑥2+𝑦2=2𝑎𝑥.

Question

Find the area of the region above the x-axis, included between the parabola $y^2 = ax$ and the circle $x^2 + y^2 = 2ax$ .

Solution

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