The boiling points of these compounds are primarily determined by the strength of their intermolecular forces. The stronger the intermolecular forces, the higher the boiling point.

1. Iodomethane (CH3I): Iodine is the largest and most polarizable of the halogens in these compounds, which means it will have the strongest London dispersion forces. Therefore, iodomethane will have the highest boiling point.

2. Dibromomethane (CH2Br2): Dibromomethane has two bromine atoms, which means it will have stronger London dispersion forces than bromomethane and chloromethane. Therefore, dibromomethane will have the second highest boiling point.

3. Bromomethane (CH3Br): Bromine is larger and more polarizable than chlorine, which means bromomethane will have stronger London dispersion forces and a higher boiling point than chloromethane.

4. Chloromethane (CH3Cl): Chlorine is the smallest and least polarizable of the halogens in these compounds, which means chloromethane will have the weakest London dispersion forces and the lowest boiling point.

So, the order of boiling points from highest to lowest is: Iodomethane Dibromomethane Bromomethane Chloromethane.

Question

The boiling points of these compounds are primarily determined by the strength of their intermolecular forces. The stronger the intermolecular forces, the higher the boiling point.

1. Iodomethane (CH3I): Iodine is the largest and most polarizable of the halogens in these compounds, which means it will have the strongest London dispersion forces. Therefore, iodomethane will have the highest boiling point.

2. Dibromomethane (CH2Br2): Dibromomethane has two bromine atoms, which means it will have stronger London dispersion forces than bromomethane and chloromethane. Therefore, dibromomethane will have the second highest boiling point.

3. Bromomethane (CH3Br): Bromine is larger and more polarizable than chlorine, which means bromomethane will have stronger London dispersion forces and a higher boiling point than chloromethane.

4. Chloromethane (CH3Cl): Chlorine is the smallest and least polarizable of the halogens in these compounds, which means chloromethane will have the weakest London dispersion forces and the lowest boiling point.

So, the order of boiling points from highest to lowest is: Iodomethane > Dibromomethane > Bromomethane > Chloromethane.

Knowee AI · Accepted Answer

The boiling points of these compounds are primarily determined by the strength of their intermolecular forces. The stronger the intermolecular forces, the higher the boiling point.

1. Iodomethane (CH3I): Iodine is the largest and most polarizable of the halogens in these compounds, which means it will have the strongest London dispersion forces. Therefore, iodomethane will have the highest boiling point.

2. Dibromomethane (CH2Br2): Dibromomethane has two bromine atoms, which means it will have stronger London dispersion forces than bromomethane and chloromethane. Therefore, dibromomethane will have the second highest boiling point.

3. Bromomethane (CH3Br): Bromine is larger and more polarizable than chlorine, which means bromomethane will have stronger London dispersion forces and a higher boiling point than chloromethane.

4. Chloromethane (CH3Cl): Chlorine is the smallest and least polarizable of the halogens in these compounds, which means chloromethane will have the weakest London dispersion forces and the lowest boiling point.

So, the order of boiling points from highest to lowest is: Iodomethane > Dibromomethane > Bromomethane > Chloromethane.

The boiling points of Iodomethane, Dibromomethane, Bromomethane,Chloromethane follow the order

Question

The boiling points of Iodomethane, Dibromomethane, Bromomethane, Chloromethane follow the order

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