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Which of the following function headers is correct?def fun(a = 2, b = 3, c)def fun(a = 2, b, c = 3)def fun(a, b = 2, c = 3)def fun(a, b, c = 3, d)

Question

Which of the following function headers is correct?

  • def fun(a = 2, b = 3, c)
  • def fun(a = 2, b, c = 3)
  • def fun(a, b = 2, c = 3)
  • def fun(a, b, c = 3, d)
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Solution

In Python, default parameters must come after non-default parameters in the function definition. Let's analyze the provided options:

  1. Option 1: def fun(a = 2, b = 3, c)

    • Incorrect because default parameters (a and b) come before a non-default parameter (c).
  2. Option 2: def fun(a = 2, b, c = 3)

    • Incorrect for the same reason; default parameter a comes before non-default parameter b.
  3. Option 3: def fun(a, b = 2, c = 3)

    • Correct because non-default parameter a comes first, followed by default parameters b and c.
  4. Option 4: def fun(a, b, c = 3, d)

    • Incorrect because default parameter c comes before non-default parameter d.

Final Answer

The correct function header is: def fun(a, b = 2, c = 3).

This problem has been solved

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