Which of the following function headers is correct?def fun(a = 2, b = 3, c)def fun(a = 2, b, c = 3)def fun(a, b = 2, c = 3)def fun(a, b, c = 3, d)
Question
Which of the following function headers is correct?
def fun(a = 2, b = 3, c)
def fun(a = 2, b, c = 3)
def fun(a, b = 2, c = 3)
def fun(a, b, c = 3, d)
Solution
In Python, default parameters must come after non-default parameters in the function definition. Let's analyze the provided options:
-
Option 1:
def fun(a = 2, b = 3, c)
- Incorrect because default parameters (
a
andb
) come before a non-default parameter (c
).
- Incorrect because default parameters (
-
Option 2:
def fun(a = 2, b, c = 3)
- Incorrect for the same reason; default parameter
a
comes before non-default parameterb
.
- Incorrect for the same reason; default parameter
-
Option 3:
def fun(a, b = 2, c = 3)
- Correct because non-default parameter
a
comes first, followed by default parametersb
andc
.
- Correct because non-default parameter
-
Option 4:
def fun(a, b, c = 3, d)
- Incorrect because default parameter
c
comes before non-default parameterd
.
- Incorrect because default parameter
Final Answer
The correct function header is: def fun(a, b = 2, c = 3)
.
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