### Break Down the Problem
1. Identify the purpose of the function `func(a)`.
2. Understand what the driver code does with that function.

### Relevant Concepts
1. The function modifies its local parameter `a` by adding `10`, but this does not affect the value of `a` outside the function scope.
2. In Python, integers are immutable, meaning the original variable outside the function does not change when the parameter is modified inside the function.

### Analysis and Detail
1. When `func(a)` is called with `a = 5`, the parameter `a` within the function becomes `15`, but this modified value is not returned to `a` in the outer scope.
2. The driver's code `print(a)` uses the original value of `a`, which remains `5`.

### Verify and Summarize
- The function does not alter the value of `a` in the outer scope.
- Therefore, the value printed out will be `5`, not `15`.

### Final Answer
None of the Above

Question

### Break Down the Problem
1. Identify the purpose of the function `func(a)`.
2. Understand what the driver code does with that function.

### Relevant Concepts
1. The function modifies its local parameter `a` by adding `10`, but this does not affect the value of `a` outside the function scope.
2. In Python, integers are immutable, meaning the original variable outside the function does not change when the parameter is modified inside the function.

### Analysis and Detail
1. When `func(a)` is called with `a = 5`, the parameter `a` within the function becomes `15`, but this modified value is not returned to `a` in the outer scope.
2. The driver's code `print(a)` uses the original value of `a`, which remains `5`.

### Verify and Summarize
- The function does not alter the value of `a` in the outer scope.
- Therefore, the value printed out will be `5`, not `15`.

### Final Answer
None of the Above

Knowee AI · Accepted Answer

### Break Down the Problem
1. Identify the purpose of the function `func(a)`.
2. Understand what the driver code does with that function.

### Relevant Concepts
1. The function modifies its local parameter `a` by adding `10`, but this does not affect the value of `a` outside the function scope.
2. In Python, integers are immutable, meaning the original variable outside the function does not change when the parameter is modified inside the function.

### Analysis and Detail
1. When `func(a)` is called with `a = 5`, the parameter `a` within the function becomes `15`, but this modified value is not returned to `a` in the outer scope.
2. The driver's code `print(a)` uses the original value of `a`, which remains `5`.

### Verify and Summarize
- The function does not alter the value of `a` in the outer scope.
- Therefore, the value printed out will be `5`, not `15`.

### Final Answer
None of the Above

def func(a): a = a + 10 return a#Driver's codea = 5func(a)print(a)Options: Pick one correct answer from below105ErrorNone of the Above

Question

Driver's code

Solution

Break Down the Problem

Relevant Concepts

Analysis and Detail

Verify and Summarize

Final Answer

Similar Questions

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