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for the equation: (x - 2)2 = - 4(y + 1); identify axis of symetryQuestion 1Select one:x = 2y = 2x = 1y = -1Clear my choice◄ weekend sheet t3 w8Jump to...

Question

For the equation:

(x2)2=4(y+1);(x - 2)^2 = -4(y + 1); identify axis of symmetry

Question 1
Select one:

  • x = 2
  • y = 2
  • x = 1
  • y = -1

Clear my choice ◄ weekend sheet t3 w8 Jump to...

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Solution

1. Break Down the Problem

The given equation is (x2)2=4(y+1)(x - 2)^2 = -4(y + 1). This is a transformed parabola. To find the axis of symmetry, we need to rewrite the equation in a standard form that reveals its properties.

2. Relevant Concepts

The standard form for a parabola that opens vertically is given by (xh)2=4p(yk)(x - h)^2 = 4p(y - k), where (h,k)(h, k) is the vertex of the parabola and the axis of symmetry is x=hx = h.

3. Analysis and Detail

  1. Rewrite the given equation: (x2)2=4(y+1) (x - 2)^2 = -4(y + 1) This can be compared with the standard form: (xh)2=4p(yk) (x - h)^2 = 4p(y - k) Here, we can identify:

    • h=2h = 2
    • k=1k = -1
    • 4p=44p = -4 which gives us p=1p = -1
  2. Since h=2h = 2, the axis of symmetry is given by the equation: x=h=2 x = h = 2

4. Verify and Summarize

We have identified the vertex of the parabola at (2,1)(2, -1) and confirmed that the axis of symmetry is the line x=hx = h.

Final Answer

The axis of symmetry for the equation (x2)2=4(y+1)(x - 2)^2 = -4(y + 1) is x=2x = 2.

This problem has been solved

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