The sum of the areas of two squares is 468 m^2: If the difference of their perimeters is 24 m, find the sides of the two squares.
Question
Solution 1
Let's denote the side of the first square as a and the side of the second square as b.
From the problem, we have two equations:
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The sum of the areas of the two squares is 468 m^2. The area of a square is given by the side length squared, so we have a^2 + b^2 = 468.
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