The coulomb's force between the 2 point charges 10µC and 5µC placed at a distance of 150cm is:Group of answer choices10 N0.5 N2 N0.2 N

To solve this problem, we need to use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula is:

F = k * |q1*q2| / r^2

where:

• F is the force between the charges,
• k is Coulomb's constant (approximately 9.0 x 10^9 N m^2/C^2),
• q1 and q2 are the amounts of charge,
• r is the distance between the charges.

Given: q1 = 10 µC = 10 * 10^-6 C (because 1 µC = 10^-6 C), q2 = 5 µC = 5 * 10^-6 C, r = 150 cm = 1.5 m (because 1 cm = 0.01 m).

Substituting these values into the formula, we get:

F = 9.0 x 10^9 * |(10 * 10^-6) * (5 * 10^-6)| / (1.5)^2 F = 9.0 x 10^9 * 50 * 10^-12 / 2.25 F = 9.0 * 50 / 2.25 * 10^-2 F = 200 N

However, none of the provided answer choices match this result. Please check the problem statement and the answer choices.